0=-16x^2+15x+120

Solution for 0=-16x^2+15x+120 equation:

0=-16x^2+15x+120

We move all terms to the left:

0-(-16x^2+15x+120)=0

We add all the numbers together, and all the variables

-(-16x^2+15x+120)=0

We get rid of parentheses

16x^2-15x-120=0

a = 16; b = -15; c = -120;
Δ = b2-4ac
Δ = -152-4·16·(-120)
Δ = 7905
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-15)-\sqrt{7905}}{2*16}=\frac{15-\sqrt{7905}}{32}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-15)+\sqrt{7905}}{2*16}=\frac{15+\sqrt{7905}}{32}
$